Question

36. Calcule as expressões.
A e B


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Answer 1

Resposta:

Explicação passo a passo:

a)

$64^{\frac{1}{3} } +\sqrt{81} -12=$

$\sqrt[3]{64} +\sqrt{81} -12=$

$\sqrt[3]{4^{3} } +9-12=$

$4+9-12=$

$13-12=1$

b)

$10+1^{\frac{2}{3} }+121^{\frac{1}{2} } =$

$10+\sqrt[3]{1^{2} } +\sqrt{121} =$

$10+\sqrt[3]{1} +11=$

$10+1+11=$

$11+11=$

$22$