Question

33. (UFPA) A raiz da equação do 1° grau
x+1 X+2 X-3 4-X
X-1 X+1 X-1 X+1
-+-16.
al-3
b) 5
c) -5
d) 3​

Answer 1

Resposta:

$\boxed{\mathtt{B}}$

Explicação passo-a-passo:

$\\ \displaystyle \mathsf{\frac{x + 1}{x - 1} - \frac{x + 2}{x + 1} = \frac{x - 3}{x - 1} + \frac{4 - x}{x + 1}} \\\\\\ \mathsf{\frac{x + 1}{x - 1} - \frac{x - 3}{x - 1} = \frac{4 - x}{x + 1} + \frac{x + 2}{x + 1}} \\\\\\ \mathsf{\frac{x + 1 - x + 3}{x - 1} = \frac{4 - x + x + 2}{x + 1}} \\\\\\ \mathsf{\frac{4}{x - 1} = \frac{6}{x + 1}} \\\\ \mathsf{6(x - 1) = 4(x + 1)} \\\\ \mathsf{6x - 6 = 4x + 4} \\\\ \mathsf{2x = 10} \\\\ \boxed{\boxed{\mathsf{x = 5}}}$