Question

32 - Determine du se u = ln(1+se^2t)

Answer 1

$u = ln(1 + { \sin }^{2}t ) \\ \frac{du}{dt} = \frac{1}{1 + { \sin}^{2}t} .2 \sin(t) \\ . \cos(t)$

$\frac{du}{dt} = \frac{ \sin(2t) }{1 + { \sin }^{2}t}$