Question

(31² - 6x + 4) + (2x² + 4x - 7
(9x2 - 4x - 3) + (3x2-10)
(5x² - 4x + 9) (8x² - 6x + 3)
(7x - 4y + 2) - (2x - 2y + 5)​

Answer 1

a)

(3x²-6x+4) + (2x²+4x-7)

3x² - 6x + 4 + 2x² + 4x - 7

3x² + 2x² - 6x + 4x + 4 - 7

5x² - 2x - 3

b)

(9x² - 4x - 3) + (3x² - 10)

= 9x² + 3x² - 4x - 3 - 10

= 12x² - 4x - 13

c)

(5x²-4x+9) - (8x²-6x+3)

5x² - 4x + 9 - 8x² + 6x - 3

5x² - 8x² - 4x + 6x + 9 -3

-3x² + 2x + 6

d)

(7x-4y+2)-(2x-2y+5)

7x-4y+2 -2x+2y-5

5x-2y-3