Question

30- Calcule as potências
A) [-¾]².[-¾]³=
B) [-⅔]³.[-⅔]².[-⅔]¹=
C)[-⅕]⁴ : [-⅕]²=
D) [-⅔]²( ² negativo) . [-½]⁵=
32-Determine as potências seguintes.
A){[(-⅔)¹]²}³=
B)[(-⅙)²]³ : (‐⅙)⁶=
C) 5-¹ : (⅕)=
D) (-⅕)-²=
33-Restaram ⅗ da mesa de João Francisco,que correspondem a R$ 36,00. De quanto mesada?
34-Considerado A=(0,3)³ , B= (1+⅓)-² e C= (+1,35)-¹,Calcule.
A) A+B+C
B) B⁰
C) A-²


Poderia me ajudar pfv

Answer 1

30-

A) [-¾]².[-¾]³ =[-3/4]²⁺³=[-3/4]⁵ =-243/1024

B) [-⅔]³.[-⅔]².[-⅔]¹ =[-2/3]³⁺²⁺¹=[-2/3]⁶ =64/729

C)[-⅕]⁴ : [-⅕]²=[-⅕]⁴⁻²=[-⅕]² =1/25

D) ficou estranho

32-

A){[(-⅔)¹]²}³= (-2/3)⁶ =64/729

B) [(-⅙)²]³ : (‐⅙)⁶= (-1/6)⁶ :  (‐⅙)⁶ = 1

C) 5-¹ : (⅕)= =(1/5) : (1/5) =1

D) (-⅕)⁻²= 5²=25

33-

3M/5=36

M=36*5/3 = R$ 60,00

34-

A) A+B+C  =(0,3)³+(1+⅓)⁻² +(1,35)⁻¹=

=(3/10)³ +(4/3)⁻² +(135/100)⁻¹

=(3/10)³ +(4/3)⁻² +(135/100)⁻¹

=(3/10)³ +(3/4)² +100/135

=27/1000 +9/16 +20/27 = 71833/54000

B) B⁰ = [(1+⅓)⁻²]⁰=1

C) A-² =[(0,3)³]⁻² =(0,3)⁻⁶ =(3/10)⁻⁶ =(10/3)⁶ =1000000/729

Answer 2

Resposta:

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