Question

3 (y-3)+4=2 [-(y-5)-4 (2y+1)]

Answer 1

3 (y-3)+4=2 [-(y-5)-4 (2y+1)]
3y- 9+4=2[-y+5 - 8y - 4]
3y-9+4= - 2y +10 - 16y-8
3y + 2y + 16y= 10 - 8 + 9 - 4
21y= 7
y = 7/21 = 1/3
y = 0.33

Answer 2

vamos lá...

3(y-3)+4=2[-(y-5)-4(2y+1)]

3y-9+4=2[-y+5-8y-4]

3y-5=2[-9y+1]

3y-5=-18y+2

3y+18y=2+5

21y=7

y=7/21   (simplificando)

y=1/3