Question

3(y-3)+4=2[-(y-5)-4(2y+1)]

Answer 1

3(y-3)+4=2[-(y-5)-4(2y+1)]
3y - 9 + 4 = 2 [ - y + 5 - 8y - 4 ]
3y - 9 + 4 = - 2y + 10 - 16y - 8
3y + 2y + 16y = 10 - 8 + 9 - 4
21y = 7
y = 7/21
y = 1/3