Question

3.(x2 - 2x) - 2. (6x2-3)
3x² + 5x -1 -(x²-5x)
(5x²-1) + 2.(2x²-x-3)
2.(2x² + 3x - 1) -2 .(x²-x-2)
Me ajuda pessoal !

Answer 1

= 3.(x^2 - 2x) - 2. (6x^2-3)
= 3x^2 - 6x - 12x^2 + 6
= - 9x^2 - 6x + 6

= 3x² + 5x -1 - (x²-5x)
= 3x^2 + 5x - 1 - x^2 + 5x
= 2x^2 + 10x - 1

= (5x²-1) + 2.(2x²-x-3)
= 5x^2 - 1 + 4x^2 - 2x - 6
= 9x^2 - 2x - 7

= 2.(2x² + 3x - 1) - 2 .(x²-x-2)
= 4x^2 + 6x - 2 - 2x^2 + 2x + 4
= 2x^2 + 8x + 2