Question

3^x-5= 27^1-x equação exponencial ajuda ae por favor :)

Answer 1

3^x-5=3^3.(1-x)
x-5=3-3x
X+3x=3+5
4x=8
X=8/4
X=2


Resposta : X=2

Answer 2

$3^{x-5} = 27^{1-x} \\ \\ 3^{x-5} = (3^3)^{1-x} \\ \\ 3^{x-5} = (3)^{3(1-x)} \\ \\ 3^{x-5} = (3)^{3-3x} \\ \\ x-5= 3-3x \\ \\ x+3x= 3+5 \\ \\ 4x= 8\qquad \to x= \frac{8}{4}\qquad \to \boxed{x=2} \\ \\ \\ 3^{x-5} = 27^{1-x} \\ \\ 3^{2-5} = 27^{1-2} \\ \\ 3^{-3} = (3^3)^{-1} \\ \\ \boxed{3^{-3} = (3)^{-3} }\ \checkmark$