Question

3(x+2)(x-1)/2* (2x+3)(x+4)/7 = 0

Answer 1

3(x+2)(x-1)/2* (2x+3)(x+4)/7 = 0

3(x² - 1x + 2x - 2)/2.(2x² + 8x + 3x + 12)/7

3(x² + 1x - 2)/2.(2x²+ 11x + 12)/7

(3x² + 3x - 6)/2.(2x² + 11x + 12)/7

(3x² + 3x - 6) (2x² + 11x + 12)

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2 x 7

6x⁴ + 33x³ + 36x² + 6x³ + 33x² + 36 - 12x² - 66x - 72

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14

6x⁴ + 33x³ + 6x³ + 36x² + 33x² - 12x² - 66x + 36 - 72

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14

6x⁴ + 39x³ + 69x² - 12x² - 66x - 36

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14

6x⁴ + 39x³ 57x² - 66x - 36

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14