Question

3(x-2)-3=2(x-2)(x+2)

Answer 1

3(x-2)-3 = 2(x-2)(x+2)
3x - 6 - 3 = 2.[x²-2²]
3x - 9 = 2x² - 8
0 = 2x² - 8 - 3x + 9
0 = 2x² - 3x + 1

a = 2 ; b = -3 ; c = 1

Δ = b²-4ac
Δ = (-3)²-4.2.1
Δ = 9 - 8
Δ = 1

x = [-b±√Δ]/2a
x = [-(-3) ± √1]/2.1
x = [3 ± 1]/2


x' = [3 + 1]/2
x' = 4/2
x' = 2


x" = [3 - 1]/2
x" = 2/2
x" = 1


S = {1, 2}




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