Question

3(x+1) - 5(x+2) > 3(x-2):

Answer 1

3.(x + 1) - 5.(x + 2) > 3.(x - 2) 3x + 3 - 5x - 10 > 3x - 6 -2x - 3x > -6 + 7 -5x > 1 (-1) 5x < -1 x < -1/5

Answer 2

3(x + 1) - 5(x + 2) > 3(x - 2)
3x + 3 - 5x - 10 > 3x - 6
3x - 5x - 3x > - 6 - 3 + 10
- 5x > 1 . (-1)
5x < - 1
x < - 1/5


S = {x∈R | x < - 1/5}