Question

3(x-1)-2x/5 =5(x-3)/6

Answer 1

$3(x-1)-\frac{2x}{5}=\frac{5(x-3)}{6}$
$\frac{3(x-1)}{1}-\frac{2x}{5}=\frac{5(x-3)}{6}$
$\frac{5*3(x-1)}{1*5}-\frac{2x}{5}=\frac{5(x-3)}{6}$
$\frac{15(x-1)}{5}-\frac{2x}{5}=\frac{5(x-3)}{6}$
$\frac{15x-15-2x}{5}=\frac{5(x-3)}{6}$
$\frac{13x-15}{5}=\frac{5(x-3)}{6}$
$(13x-15)*(6)=(5)*(5*(x-3))$
$78x-90=25x-75$
$53x=15$
$x=\frac{15}{53}$