Question

3)Use a regularidade do quadrado da diferença e calcule:
a)(a-5)²=
b)(4x-6)²=
c)(5-f)²=
d)(x-10)(x-10)=
e)(y²-x)²=
f)(x-6w)²=
4)Calcule os seguintes produtos:
a)(5a + c)(5a –c)=
b)(5x – 8)(5x +8)=
c)(4x+4y)(4x-4y)=
d)(3x-4)(3x+4)=

help me please

Answer 1

Resposta:

3)

a)a²-10a+25

b)16x²-48x+36

c)25-10f+f²

d)x²-20x+100

e)y⁴-2xy²+x²

f)x²-12wx+36w

4)

a)25a²-c

b)25x²-64

c)16x²-16y²

d)9x²-16

Explicação:

3)

a)(a-5)² =

(a-5)×(a-5) =

[a×a]+[a×(-5)]+[-5×a]+[-5×(-5)] =

a²+(-5a)+(-5a)+25 =

a²-5a-5a+25 =

a²-10a+25

b)(4x-6)² =

(4x-6)×(4x-6) =

[4x×4x]+[4x×(-6)]+[-6×4x]+[-6×(-6)] =

16x²+(-24x)+(-24)+36 =

16x²-24x-24x+36 =

16x²-48x+36

c)(5-f)² =

(5-f)×(5-f) =

[5×5]+[5×(-f)]+[-f×5]+[-f×(-f)] =

25+(-5f)+(-5f)+f² =

25-5f-5f+f² =

25-10f+f²

d)(x-10)×(x-10) =

[x×x]+[x×(-10)]+[-10×x]+[-10×(-10)] =

x²+(-10x)+(-10x)+100 =

x²-10x-10x+100 =

x²-20x+100

e)(y²-x)² =

(y²-x)×(y²-x) =

[y²×y²]+[y²×(-x)]+[-x×y²]+[-x×(-x)] =

y⁴+(-xy²)+(-xy²)+x² =

y⁴-xy²-xy²+x² =

y⁴-2xy²+x²

f)(x-6w)² =

(x-6w)×(x-6w) =

[x×x]+[x×(-6w)]+[-6w×x]+[-6w×(-6w)] =

x²+(-6wx)+(-6wx)+36w =

x²-6wx-6wx+36w =

x²-12wx+36w