3) Um automóvel percorre uma estrada retilínea AB, onde M é o ponto médio, sempre no mesmo sentido. A velocidade média no trecho AM é de 100 km/h e no trecho MB é de 150 km/h. A velocidade média entre os pontos A e B vale: a) 100 km/h. b) 110 km/h. c) 120 km/h. d) 130 km/h.
Soluções para a tarefa
Respondido por
2
Trecho 1



Trecho 2






Alternativa C
Trecho 2
Alternativa C
Perguntas interessantes