Question

3-Sendo A=8x²-7 X-5;B=3X²-4X+2 E C=-2X²+9X+3,Determine:

a) A+B=

b) A+B+C=

c) B-A=

d) C-B-A=

e) A+C=

f) A-C=

g) B-C=

h) B-A-C=

i) B+C=

j) B-C=

k) C-A=

l) 2A+3B-4C=



ME AJUDEM POR FAVOR

Answer 1

Resposta:

a) A+B=

$8 {x}^{2} - 7x - 5 + 3 {x}^{2} - 4x + 2 \\ 11 {x}^{2} - 11x - 3$

b) A+B+C=

$8 {x}^{2} - 7x - 5 + 3 {x}^{2} - 4x + 2 + ( - 2 {x}^{2} + 9x + 3) \\ 11 {x}^{2} - 11x - 3 - 2 {x}^{2} + 9x + 3 \\ 9 {x}^{2} - 2x$

c) B-A=

$3 {x}^{2} - 4x + 2 - (8 {x}^{2} - 7x - 5) \\ 3 {x}^{2} - 4x + 2 - 8 {x}^{2} + 7x + 5 \\ - 5 {x}^{2} + 3x + 7$

d) C-B-A=

$- 2 {x}^{2} + 9x + 3 - (3 {x}^{2} - 4x + 2) - (8 {x}^{2} - 7x - 5) \\ - 2 {x}^{2} + 9x + 3 - 3 {x}^{2} + 4x - 2 - 8 {x}^{2} + 7x + 5 \\ - 13 {x}^{2} + 20x + 6$

e) A+C

$8 {x}^{2} - 7x + 5 + ( - 2 {x}^{2} + 9x +3 ) \\ 8 {x}^{2} - 7x + 5 - 2 {x}^{2} + 9x + 3 \\ 6 {x}^{2} + 2x + 8$

f) A-C=

$8 {x}^{2} - 7x + 5 - ( - 2 {x}^{2} + 9x + 3) \\ 8 {x}^{2} - 7x + 5 + 2 {x}^{2} - 9x - 3 \\ 10 {x}^{2} - 16x + 2$

g) B-C=

$3 {x}^{2} - 4x + 2 - ( - 2 {x}^{2} + 9x + 3) \\ 3 {x}^{2} - 4x + 2 + 2 {x}^{2} - 9x - 3 \\ 5 {x}^{2} - 13x - 1$

h) B-A-C=

$3 {x}^{2} - 4x + 2 - (8 {x}^{2} - 7x - 5) - ( - 2 {x}^{2} + 9x + 3) \\ 3 {x}^{2} - 4x + 2 - 8 {x}^{2} + 7x + 5 + 2 {x}^{2} - 9x - 3 \\ - 3 {x}^{2} - 6x + 4$

i) B+C=

$3 {x}^{2} - 4x + 2 + ( - 2 {x}^{2} + 9x + 3) \\ 3 {x}^{2} - 4x + 2 - 2 {x}^{2} + 9x + 3 \\ {x}^{2} + 5x + 5$

j) B-C=

$3 {x}^{2} - 4x + 2 - ( - 2 {x}^{2} + 9x + 3) \\ 3 {x}^{2} - 4x + 2 + 2 {x}^{2} - 9x - 3 \\ 5 {x}^{2} - 13x - 1$

k) C-A=

$- 2 {x}^{2} + 9x + 3 - (8 {x}^{2} - 7x - 5) \\ - 2 {x}^{2} + 9x + 3 - 8 {x}^{2} + 7x - 5 \\ - 10 {x}^{2} + 16x - 2$

l) 2A+3B-4C=

$2 \times (8 {x}^{2} - 7x - 5) + 3 \times (3 {x}^{2} - 4x + 2) - 4 \times ( - 2 {x}^{2} + 9x + 3) \\ 16 {x}^{2} - 14x - 10 + 9 {x}^{2} - 12x + 6 + 8 {x}^{2} - 36x - 12 \\ 33 {x}^{2} - 62x - 16$