Question

3. Seja a função f: R R, definida por y = x2 + 2x - 3. Calcule f(-3), f(-2), f(-1), f(0), f(1) e f(2)​

Answer 1

y = x² + 2x - 3

f(-3) = (-3)² + 2 . (-3) - 3

f(-3) = 9 + (-6) - 3

f(-3) = 9 - 6 - 3

f(-3) = 9 - 9

f(-3) = 0

f(-2) = (-2)² + 2 . (-2) - 3

f(-2) = 4 + (-4) - 3

f(-2) = 4 - 4 - 3

f(-2) = 4 - 7

f(-2) = - 3

f(-1) = (-1)² + 2 . (-1) - 3

f(-1) = 1 + (-2) - 3

f(-1) = 1 - 2 - 3

f(-1) = 1 - 5

f(-1) = - 4

f(0) = 0² + 2 . 0 - 3

f(0) = 0 + 0 - 3

f(0) = - 3

f(1) = 1² + 2 . 1 - 3

f(1) = 1 + 2 - 3

f(1) = 1 - 1

f(1) = 0

f(2) = 2² + 2 . 2 - 3

f(2) = 4 + 4 - 3

f(2) = 4 + 1

f(2) = 5