3-Resolua ob sistemas
a) 5x+4y=1
3x+7y=2
b) x +2y +Z= -5
y+ = -3
Soluções para a tarefa
Resposta:
a) x+4y=3 4y=3-x
x-4y=7 4y=3-5
2x=10 4y=-2
x=10/2 y=-2/4( simplificando por 2)
x=5 y=-1/2 s(5,-1/2)
b)3x+7y=1 3x+7Y=1
-3x-4y=2 3X+7.1=1
3y=3 3X+7=1
y=3/3 3X=1-7
y=1 3X=-6 S(-2,1)
X=-6/3
X=-2
C)X+3Y=2 -5-2Y=3 X+3Y=2
-2Y=3+5 X+3.(-4)=2
-2Y=8(-) X-12=2
2Y=-8 X=2+12
Y=-8/2 X=14
Y=-4 S(14,-4)
D)4X+2Y=5 4X+2Y=5 4X+2Y=5
-3X-Y=1.(2) -6X-2Y=2 4X+2.(-7/2)=5
-2Y=7 4X-7=5
Y=7/-2 4X=5+7
Y=-7/2 4X=12
X=12/4
X=3 S(3,-7/2)
E)5X+7Y=15
-3X-7Y=17 5X+7Y=15
2X=32 5.16+7Y=15
X=32/2 80+7Y=15
X=16 7Y=15-80 S(16,-65/7)
7Y=-65
Y=-65/7
Explicação passo-a-passo: