Question

3. O inverso do numero complexo z = - 3 +6i

Answer 1

$\frac{1}{ - 3 + 6i} \\ = \frac{1}{(- 3 + 6i)} \frac{( - 3 - 6i)}{( - 3 - 6i)}$

$\frac{ - 3 - 6i}{( { - 3)}^{2} - {(6i)}^{2} } = \frac{ - 3 - 6i}{9 - ( - 36)} \\ = \frac{ - 3 - 6i}{9 + 36} = \frac{ - 3 - 6i}{45}$

$\frac{ - 1 - 2i}{15} \:$