Question

(3+h)^-1 -3^-1 sobre h limite de h tendendo a 0

Answer 1

Resposta:

[(3+h)^-1 -3^-1]/h=

[1/(3+h)-1/3]/h=

[(3-3-h)/3h+9]/h=

[-h/(3h+9)]/h=

-h/3h²+9h=

-1/3h+9=

-1/3(0)+9=

-1/9