Question

3 elevado a 2 vezes 4 elevado a -2 e (1/3+1/2)elevado a -3

Answer 1

$3^2.4^{-2} = 9 . \frac{1}{4^2} = \frac{9}{16}\\\\ ( \frac{1}{3}+\frac{1}{2})^{-3} = (\frac{2+3}{6})^{-3} = (\frac{5}{6})^{-3}= \frac{1}{( \frac{5}{6})^3} = (\frac{6}{5})^3= \frac{216}{125}$

bons estudos!!