Question

3) Determinar as raízes da equação.
a) x2 + 12x – 35 = 0
b) – x2 + 25x = 0
c) – 3x2 + 144 = 0
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Answer 1

Resposta:

Explicação passo-a-passo:

x²+12x-35=0

-12+/-$\frac{+}{-} \sqrt{12^{2} -4.(-35)}$

                           2

$\frac{-12\frac{+}{-} \sqrt{144+140} }{2}$

$\frac{-12\frac{+}{-} \sqrt{284} }{2}$$\frac{-12\frac{+}{-} 2\sqrt{71} }{2} \\x'=\frac{-12+2\sqrt{71} }{2} =-6+\sqrt{71} \\x"=\frac{-12-2\sqrt{71} }{2} =-6-\sqrt{71}$