Matemática, perguntado por manoelaniziosilva, 9 meses atrás

3 ) Calcule o valor de x nas proporções:

a )
 \frac{x}{5}  =   \frac{6}{10}

b )
 \frac{3}{7}  =  \frac{60}{x}

c )
 \frac{6}{x}  =  \frac{14}{35}

d )
 \frac{7}{6}  =  \frac{42}{x}

e )
 \frac{2x}{3}  =  \frac{8}{6}

f )
 \frac{2x}{15}  =  \frac{6}{9}
g)

 \frac{5}{x + 4}  =  \frac{30}{54}

h )
 \frac{6}{7}  =  \frac{3x}{28}

Soluções para a tarefa

Respondido por Usuário anônimo
1

Explicação passo-a-passo:

a)

\sf \dfrac{x}{5}=\dfrac{6}{10}

\sf 10x=5\cdot6

\sf 10x=30

\sf x=\dfrac{30}{10}

\sf \red{x=3}

b)

\sf \dfrac{3}{7}=\dfrac{60}{x}

\sf 3x=7\cdot60

\sf 3x=420

\sf x=\dfrac{420}{3}

\sf \red{x=140}

c)

\sf \dfrac{6}{x}=\dfrac{14}{35}

\sf 14x=6\cdot35

\sf 14x=210

\sf x=\dfrac{210}{14}

\sf \red{x=15}

d)

\sf \dfrac{7}{6}=\dfrac{42}{x}

\sf 7x=6\cdot42

\sf 7x=252

\sf x=\dfrac{252}{7}

\sf \red{x=36}

e)

\sf \dfrac{2x}{3}=\dfrac{8}{6}

\sf 6\cdot2x=3\cdot8

\sf 12x=24

\sf x=\dfrac{24}{12}

\sf \red{x=2}

f)

\sf \dfrac{2x}{15}=\dfrac{6}{9}

\sf 9\cdot2x=15\cdot6

\sf 18x=90

\sf x=\dfrac{90}{18}

\sf \red{x=5}

g)

\sf \dfrac{5}{x+4}=\dfrac{30}{54}

\sf 30\cdot(x+4)=5\cdot54

\sf 30x+120=270

\sf 30x=270-120

\sf 30x=150

\sf x=\dfrac{150}{30}

\sf \red{x=5}

h)

\sf \dfrac{6}{7}=\dfrac{3x}{28}

\sf 7\cdot3x=6\cdot28

\sf 21x=168

\sf x=\dfrac{168}{21}

\sf \red{x=8}

Respondido por iurymat
0

Resposta:

a) 10x = 6×5 => × = 3.

b) 60×7 = 3x => x = 16.

c) 14x = 35 × 6 => x = 15.

d)42×6 = 7x => x = 36.

e)2x×6 = 3 × 8 => x = 2.

f)2x × 9 = 15 × 6 => x = 5.

g)30(x + 4) = 54 × 5 => 30x + 120 = 270

x = 150 / 30 == > x = 5.

h)28 × 6 = 7 × 3x => x = 8.

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