Question

3)Calcule a distância entre os pontos dados:
a)A(3,-1 ) e B(3,5)​

Answer 1

Resposta:

ab = 6.

Explicação passo-a-passo:

AB=√(xa-xb)²+(ya-yb)²

AB=√(3-3)²+(-1-5)²

AB=√(0)²+(-6)²

AB=√ 0 + 36

AB=√36

AB=6.

DE NADA ;-;

ACHO Q TA CERTO.

Answer 2

✅ Finalizando os cálculos, concluímos que o valor da distância entre os referidos pontos é:

  $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf d(A, B) = 6\:u.\:c.\:\:\:}}\end{gathered} }$

Sejam os pontos:

                 $\Large\begin{cases} A(3, -1)\\B(3, 5)\end{cases}$

Para calcular a distância entre os referidos pontos fazemos:

  $\Large\displaystyle\text{ \begin{gathered} d(A, B) = \sqrt{(X_{B} - X_{A})^{2} + (Y_{B} - Y_{A})^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{(3 - 3)^{2} + (5 - (-1))^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{0^{2} + (5 + 1)^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{0^{2} + 6^{2}}\end{gathered} }$

                    $\Large\displaystyle\begin{gathered} = \sqrt{36}\end{gathered}$

                    $\Large\displaystyle\begin{gathered} = 6\end{gathered}$

✅ Portanto, a distância é:

   $\Large\displaystyle\begin{gathered} d(A, B) = 6\:u.\:c.\end{gathered}$

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered} }$

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$\Large\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Observe \:o\:Gr\acute{a}fico!!\:\:\:}}}\end{gathered} }$