Question

3) Calcular a, sendo b = 11 e θ = 45º​

Answer 1

Resposta:

$a=11\sqrt{2}$

Explicação passo-a-passo:

Utilizando o seno de 45°, obtemos:

$\text{sen}~45^{\circ}=\dfrac{11}{a}$

$\dfrac{\sqrt{2}}{2}=\dfrac{11}{a}$

$\sqrt{2}\cdot a = 22$

$a=\dfrac{22}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}$

$a=\dfrac{22\sqrt{2}}{2}$

$\boxed{a=11\sqrt{2}}$