Matemática, perguntado por karenkssilvak725, 4 meses atrás

3.{4³-[.6⁰+7.(9²-80)]}​

Soluções para a tarefa

Respondido por Usuário anônimo
2

Resposta:

3\left\{4^3-\left[6^0+7\left(9^2-80\right)\right]\right\}\\\\6^0+7\left(9^2-80\right)\\\\9^2-80\\\\9^2\\\\9^2=81\\\\=81-80\\\\81-80=1\\\\=6^0+7\cdot \:1\\\\6^0=1\\\\=1+7\cdot \:1\\\\1=null\\\\=7\cdot \:1\\\\7\cdot \:1=7\\\\=4^3-7\\\\4^3=64\\\\=64-7\\\\64-7=57\\\\=3\cdot \:57\\\\3\cdot \:57=171\\\\=171

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