Question

(3,4) e (2,1) a distância

Answer 1

$a~(3~;~4)~~~e~~~b~(2~;~1)\\\\\\ d_{ab}= \sqrt{(x_b-x_a)^2+(y_B-y_a)^2}\\\\\\d_{ab}= \sqrt{(2-3)^2+(1-4)^2}\to\\\\ d_{ab}= \sqrt{(-1)^2+(-3)^2}\to\\\\ d_{ab}= \sqrt{1+9}\to\\\\ \boxed{d_{ab}= \sqrt{10~}}$