Question

[(3^4:27+✓64+6^2)^2:13+0^13:1^13*2^3]*(✓625-4^2)

Answer 1

Boa tarde.

$[(3^4:27+ \sqrt64+6^2)^2:13+0^13:1^13*2^3]*( \sqrt625-4^2) = [(81:27+8+36) : 13 + 0 : 1 . 8] . (25-16) = [(3+8+36) : 13 + 0 : 1 . 8] . 9 = [47 : 13 +0 : 1 . 8] . 9 = 3,61 + 0 . 8 . 9 = 3,61 + 0 . 9 = 3,61 + 0 = 3,61$

Bons estudos! :-)