Question

(-3-4)²:(-49)+[20-(10-√81)²+(-2)³+(3)²]

Answer 1

(-3-4)^2 ÷(-49)+[20-(10-raiz de 81)^2 + (-2)^3 + (3)^2]

-7^2 ÷(-49)+[20-(10-9)^2+ (-8) + 9]

-49÷ (-49) +[20-(1)^2 + (-8)+9]

0+ [20 + 1 -8 +9]

21+1

22