Question

(3^4)^1-raiz quadrada de 128 elevado a 7 potencia- 256^0

Answer 1

(3^4)^1 - rz128^7 - 256^0 = 81 - (rz2^7)^7 - (2^8)^0 = 81 - (2^3.rz2)^7 - 0 = 81 - (2^3)^7. (2^7/2) = 81 - 2^21 . 2^7^2 = 81 - 2^49/2 =

3^4 - 2^24.rz2