Question

3/2x + 41/8x??????????????

Answer 1

Resposta: $\frac{53}{8x}$

Explicação passo-a-passo:

$\frac{3}{2x} + \frac{41}{8x}$ =

mmc = 16x²

$\frac{(16x^2 : 2x) . 3}{16 x^2} + \frac{(16 x^2 : 8x) . 41)}{16x ^2}$=

$\frac{8x . 3}{16 x^2} + \frac{ 2x . 41}{16 x ^2}$ =

$\frac{24x}{16 x^2} + \frac{82x}{16 x^2}$ =

$\frac{106x}{16x^2}$ =

$\frac{106x : 2x}{16 x^2 : 2x}$ =

$\frac{53}{8x}$