Question

(-3/2ab) . (+4/9bc) . (-3/7ac) resposta

Answer 1

$(- \frac{3}{2} ab)\times( \frac{4}{9} bc)\times(- \frac{3}{7} ac)= \\ \\ (- \frac{3}{\not2} ).( \frac{\not4^2}{\not9_3} ).(- \frac{\not3}{7} )a^{1+1}.b.c^{1+1}= \\ \\ (-\not3). \frac{2}{\not3}.(- \frac{1}{7} )a^2bc}2= \\ \\ simplificando \\ \\ + \frac{2}{7} a^2bc^2$