Question

(3^2-2^3)*3^3-2^3+2^2*4^2 como armar me ajudem prfvr

Answer 1

$(3^2-2^3)\times3^3-2^3+2^2\times4^2= \\ \\ (9-8)\times27-8+4\times16= \\ \\ (+1)\times27-8+64= \\ \\ 27-8+64= \\ \\ 91-8=83$