Question

(-3√2+2) (3√2+2) gostaria de saber a resposta dessa conta com radicais

Answer 1

$(-3\sqrt{2} + 2) . (3\sqrt{2} + 2)\\ \\ -3\sqrt{2}. 3\sqrt{2} - 3\sqrt{2} . 2 + 2.3\sqrt{2} + 2.2\\ \\ -3\sqrt{2}. 3\sqrt{2} - 3\sqrt{2} . 2 + 2.3\sqrt{2} + 2.2\\ \\ -3\sqrt{2}. 3\sqrt{2} + 4 \\ \\ -3.3 ( \sqrt{2}^2 + 4 \\ \\ -9.2 + 4\\ \\ -18 + 4 = -14$

Answer 2

= (-3√2+2) . (3√2+2)
= -3√2.3√2 +2.(-3√2) +2.3√2+2.2
= -9.2 -6√2+6√2+4
= -18+4
= - 14