Question

³√1-3x = - 1 R: {2/3}

Answer 1

$\sqrt[3]{1-3x}=-1\\\\(\sqrt[3]{1-3x})^3=(-1)^3\\\\1-3x=-1\\\\-3x=-1-1\\\\-3x=-2\\\\\\x= \dfrac{2}{3}$

Answer 2

Resposta:

$\sqrt[3]{1 - 3x} = - 1 \\ 1 - 3x = { - 1}^{3} \\ 1 - 3x = - 1 \\ - 3x = - 1 - 1 \\ - 3x = - 2 \\ x = - 2/ - 3 \: \: \: \: \: \: \: \: \times ( - 1) \\ x = 2/ 3$

• Espero ter ajudado.