Matemática, perguntado por Mandinhatavaresmani, 1 ano atrás

3*{-1+12[-13+4(1-1/3)-1]-1}

Soluções para a tarefa

Respondido por TesrX
36
Olá.

Temos a expressão:
\mathsf{3\cdot\left\{-1+12\left[-13+4\left(1-\dfrac{1}{3}\right)-1\right]-1\right\}}

Vamos aos cálculos:
\mathsf{3\cdot\left\{-1+12\left[-13+4\left(1-\dfrac{1}{3}\right)-1\right]-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+12\left[-13+4\left(\dfrac{1\cdot3-1}{3}\right)-1\right]-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+12\left[-13+4\left(\dfrac{3-1}{3}\right)-1\right]-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+12\left[-13+4\left(\dfrac{2}{3}\right)-1\right]-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+12\left[-13+\dfrac{4\cdot2}{3}-1\right]-1\right\}=}

\mathsf{3\cdot\left\{-1+12\left[-14+\dfrac{8}{3}\right]-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+12\left[\dfrac{-14\cdot3+8}{3}\right]-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+12\left[\dfrac{-42+8}{3}\right]-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+12\left[\dfrac{-34}{3}\right]-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+\dfrac{12\cdot(-34)}{3}-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1+\dfrac{-408}{3}-1\right\}=}\\\\\\\mathsf{3\cdot\left\{-1-136-1\right\}=}\\\\\mathsf{3\cdot\left\{-138\right\}=}\\\\\boxed{\mathsf{-414}}

Qualquer dúvida, deixe nos comentários.
Bons estudos.
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