Question

2x²+x-3=0 me ajudem pfvr

Answer 1

$\sf 2x^2+x-3=0$

$\sf \Delta=1^2-4\cdot2\cdot(-3)$

$\sf \Delta=1+24$

$\sf \Delta=25$

$\sf x=\dfrac{-1\pm\sqrt{25}}{2\cdot2}=\dfrac{-1\pm5}{4}$

$\sf x'=\dfrac{-1+5}{4}~\Rightarrow~x'=\dfrac{4}{4}~\Rightarrow~\red{x'=1}$

$\sf x"=\dfrac{-1-5}{4}~\Rightarrow~x"=\dfrac{-6}{4}~\Rightarrow~\red{x"=\dfrac{-3}{2}}$