Question

2x² - 7x + p = 0



PRECISO URGENTE

Answer 1

Resposta:

$2x {}^{2} - 7 + p = 0 = \\ 2x {}^{2} - 7 + p = 0 \\ 2x {}^{2} + ( - 7x) + p = 0 \\ a = 2. \: b = - 7. \: c = p \\ 2x {}^{2} - 7x + p = 0 \\ a = . \: b) = - 7 \: c)p \\x = \frac{ - ( - 7) + \sqrt{(7) {}^{2} - 4} \times 2p}{2 \times 2} \\ x = \frac{ - 7 + \sqrt{( - 7) {}^{2} - 4 \times 2p} }{2 \times 2} \\ x = \frac{ - ( - 7) + \sqrt{( - 7) {}^{2} - 4 \times 2p} }{2 \times 2} \\ ( - 7) {}^{2} \\ 7 {}^{2} \\ 7 \times 7 \\ 49 \\ x = \frac{ - (7) + \sqrt{(( - 7) {}^{2} - 4 \times 2p }}{2 \times 2} \\ x = \frac{7 + \sqrt{49 - 4 \times 2p} }{2 \times 2} \\ x = \frac{ - ( - 7) + \sqrt{( - 7) {}^{2} - 4 \times 2p} }{2 \times 2} \\ - 4 \times 2p \\ - (4 \times 2)p \\ - 8p \\ \times = \frac{ - ( - 7) + \sqrt{( - 7) {}^{2} - 4 \times 2p } }{2 \times 2} \\ x = \frac{7 + \sqrt{49 - 8p} }{2xp} \\ x = \frac{ - ( - 7 + \sqrt{( - 7) {}^{2} - 4 \times2p } }{2 \times 2} \\ x = \frac{7 + \sqrt{49 - 8p} }{4} \\ x = \frac{7 + \sqrt{49 - 8p} }{4} \\ x = \frac{7 - \sqrt{49 - 8p} }{4} \\ resposta \\ x = \frac{7 + \sqrt{49 - 8p} }{4} \\x = \frac{7 - \sqrt{49 - 8p} }{4}$