Question

-2x²+6x-4 alguém responde e

Answer 1

Resposta:

$-2x^{2} +6x-4=0\\ \\ coeficientes:\\a=-2\\ b=6\\ c=-4\\ \\ delta=b^{2} -4.a.c\\ \\ delta=6^{2} -4.(-2).(-4)\\ \\ delta=36-32\\ \\ delta=4\\ \\ \\ x=\frac{-b+-\sqrt{delta} }{2.a} \\ \\ x=\frac{-6+-\sqrt{4} }{2.(-2)} \\ \\ x=\frac{-6+-2}{-4} \\ \\ x'=\frac{-6+2}{-4} =\frac{-4}{-4} =+1\\ \\ x''=\frac{-6-2}{-4} =\frac{-8}{-4} =+2\\ \\ \\ S\left \{ {{1;2} {}} \}$