Question

2x² - 5x - 3 = 0
preciso do delta ​

Answer 1

✅ Após resolver os cálculos, concluímos que o valor do delta - discriminante -  da equação do segundo grau é:

       $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf \Delta = 49\:\:\:}}\end{gathered} }$

Seja a equação do segundo grau:

    $\Large\displaystyle\begin{gathered} 2x^{2} - 5x - 3 = 0\end{gathered}$

Cujos coeficientes são:

             $\Large\begin{cases} a = 2\\b = -5\\c = -3\end{cases}$

Para calcular o valor do delta devemos fazer:

         $\Large\displaystyle\begin{gathered} \Delta = b^{2} - 4ac\end{gathered}$

               $\Large\displaystyle\begin{gathered} = (-5)^{2} - 4\cdot2\cdot(-3)\end{gathered}$

               $\Large\displaystyle\begin{gathered} = 25 + 24\end{gathered}$

               $\Large\displaystyle\begin{gathered} = 49\end{gathered}$

✅ Portanto, o valor do delta é:

          $\Large\displaystyle\begin{gathered} \Delta = 49\end{gathered}$

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered} }$

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Answer 2

$2x^2-5x-3=0$

$a=2\quad b=-5\quad c=-3$

$\Delta=b^2-4\cdot a\cdot c$

$\Delta=(-5)^2-4\cdot2\cdot(-3)$

$\Delta=25+24$

$\boxed{\boxed{\Delta=49}}$