Question

2x2-4x+1=0 urgente por favor​

Answer 1

Explicação passo-a-passo:

$\sf 2x^2-4x+1=0$

$\sf \Delta=b^2-4\cdot a\cdot c$

$\sf \Delta=(-4)^2-4\cdot2\cdot1$

$\sf \Delta=16-8$

$\sf \Delta=8$

$\sf x=\dfrac{-b\pm\sqrt{\Delta}}{2\cdot a}$

$\sf x=\dfrac{-(-4)\pm\sqrt{8}}{2\cdot2}=\dfrac{4\pm2\sqrt{2}}{4}$

$\sf x'=\dfrac{4+2\sqrt{2}}{4}~\longrightarrow~x'=\dfrac{2+\sqrt{2}}{2}$

$\sf x"=\dfrac{4-2\sqrt{2}}{4}~\longrightarrow~x"=\dfrac{2-\sqrt{2}}{2}$

$\sf S=\left\{\dfrac{2+\sqrt{2}}{2},\dfrac{2-\sqrt{2}}{2}\right\}$