2x²-16x+32=0 formula de delta e baskara
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2x²-16x+32=0
a=2 b= -16 c=32
∆=b²-4.a.c
∆=(-16)²-4.2.32
∆=256-256
∆=0
X= -b±√∆/2.a
X=-(-16)±√0/2.2
X=16±0/4
X'=16+0/4=16/4=4/4=1
X"=16-0/4=16/4=4/4=1
S={1;1}
a=2 b= -16 c=32
∆=b²-4.a.c
∆=(-16)²-4.2.32
∆=256-256
∆=0
X= -b±√∆/2.a
X=-(-16)±√0/2.2
X=16±0/4
X'=16+0/4=16/4=4/4=1
X"=16-0/4=16/4=4/4=1
S={1;1}
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