Question

2x²-10+8x=0 quem sabe?

Answer 1

Resposta:

x'=(-5)

x''=1

Explicação passo a passo:

$2x^{2} -10+8x=0\\\\2x^{2} +8x-10=0\\\\\frac{2x^{2} +8x-10}{2} =\frac{0}{2} \\\\x^{2} +4x-5=0$

$x=\frac{-4\pm\sqrt{4^{2} -4.1.(-5)} }{2.1}\\\\x=\frac{-4\pm\sqrt{16 -4.(-5)} }{2}\\\\x=\frac{-4\pm\sqrt{16 +20} }{2}\\\\x=\frac{-4\pm\sqrt{36} }{2}\\\\x=\frac{-4\pm\sqrt{6^{2} } }{2}\\\\x=\frac{-4\pm6 }{2}\\\\x=-2\pm3\\\\\\\\x'=-2-3\\\\x'=-5\\\\\\\\x''=-2+3\\\\x''=1$