Question

2x +y+z=3. -2x+2y-z=0. 3x +y+z=1. PRECISOOOOO URGENTE ​

Answer 1

$\begin{bmatrix}2x+y+z=3\\ -2x+2y-z=0\\ 3x+y+z=1\end{bmatrix}\\\\\begin{bmatrix}-2\cdot \frac{3-y-z}{2}+2y-z=0\\ 3\cdot \frac{3-y-z}{2}+y+z=1\end{bmatrix}\\\\\begin{bmatrix}3y-3=0\\ \frac{-y-z+9}{2}=1\end{bmatrix}\\\\\begin{bmatrix}\frac{-1-z+9}{2}=1\end{bmatrix}\\\\\mathrm{Substituir\:}y=1\\\\\begin{bmatrix}\frac{-1-z+9}{2}=1\end{bmatrix}\\\\\begin{bmatrix}\frac{-z+8}{2}=1\end{bmatrix}\\\\\mathrm{Para\:}x=\frac{3-y-z}{2}\\\\\mathrm{Substituir\:}z=6,\:y=1\\\\x=\frac{3-1-6}{2}\\\\x=-2$

$x=-2,\:z=6,\:y=1$