Question

2x (x+3) = x2 +3x+70? como resolver?​

Answer 1

Resposta:

2x * (x+3) = x² +3x+70

2x²+6x= x² +3x+70

x²+6x= 3x+70

x²+3x= 70

x²+3x-70=0

x'=[-3+√(9+4*70)]/2 =(-3+17)/2=7

x''=[-3-√(9+4*70)]/2 =(-3-17)/2=-10

x=7  ou x=-10