Question

2x elevado a 2 - 11x + 15 = 0

Answer 1

Ola´, Alinebiliaporto!

2x² - 11x + 15 = 0
a = 2
b = -11
c = 15

Δ = b² - 4.a.c
Δ = (-11)² - 4.2.15
Δ = 121 - 120
Δ = 1

-b +- √Δ / 2.a
-(-11) +- √1 / 2.2
11 +- 1 / 4

x' = 11+1/4 = 12/4 = 3
x'' = 11-1/4 = 10:2/4:2 = 5/2 

Answer 2

Resolução por Bhaskara:

$2x^2 - 11x + 15 = 0$
a=2,b=−11, c=15

Δ=b2−4ac
Δ=(−11)2−4*(2)*(15)
Δ=121−120
Δ=1
$x = \frac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ x = \frac{-(-11) \pm \sqrt{1}}{2*2} \\ \\ x = \frac{11 \pm \sqrt{1}}{4} \\ \\ x = \frac{11 \pm 1}{4} \\ \\ x' = \frac{11 + 1}{4} \\ \\ x' = \frac{12}{4} \\ \\ x' = 3 \\ \\ \\ x'' = \frac{11- 1}{4} \\ \\ x'' = \frac{10}{4} \\ \\ x'' = \frac{5}{2}$

S= {$3, \frac{5}{2}$}