Question

2x ao quadrado menos 4x =0 na formula de bhaskara pfv

Answer 1

Olá!!  :)

$\sf x^{2} \ - \ 4x \ = \ 0 \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ a \ = \ 2 \ \ \ \ ; \ \ \ \ b = -4 \ \ \ \ ; \ \ \ \ c = 0 \\\\ \\\\ \Delta \ = \ b^{2} \ - \ 4ac \\\\ \Delta \ = \ (-4)^{2} \ - \ 4 \ . \ 2 \ . \ 0 \\\\ \Delta \ = \ 16$

$x' \ = \ \frac{-b \ \ + \ \ \sqrt{\Delta}}{2a} \\\\ x' \ = \ \frac{-(-4) \ \ + \ \ \sqrt{16}}{2 \ . \ 2} \\\\ x' \ = \ \frac{4 \ + \ 4}{4} \\\\ x' \ = \ \frac{8}{4} \\\\ \boxed{x' \ = \ 2}$                  $\sf x'' \ = \ \frac{-b \ \ - \ \ \sqrt{\Delta}}{2a} \\\\ x'' \ = \ \frac{-(-4) \ \ - \ \ \sqrt{16}}{2 \ . \ 2} \\\\ x'' \ = \ \frac{4 \ - \ 4}{4} \\\\ x'' \ = \ \frac{0}{4} \\\\ \boxed{x'' \ = \ 0}$

Resposta:

$S \ = \ \{2, \ 0 \}$

Espero ter ajudado, bons estudos!!  :)

Answer 2

Resposta:

2x² - 4x = 0

coeficientes

a=2

b=-4

c=0

Δ=b²-4ac

Δ= (-4)²-4(2)(0)

Δ= 16-0

Δ = 16

x=( -b±√Δ)/2a

x= [-(-4)±√16]/2(2)

x= (4±4)/4

x'=(4+4)/4=8/4 = 2

x"= (4-4)/4=0/4=0

S= { 0,2}