Question

2x ao quadrado - 8x + 8 = 0 ????

Answer 1

2x²-8x+8=0                              a=2    b=-8     c=8

Δ=b²-4.a.c
Δ= (-8)²-4.2.8
Δ=64-64
Δ=0               ⇒as duas raizes sao reais e iguais


x=-(-8) (+ ou-)√0         8+ ou - 0
   _____________ = _____________    x'=x"=2
         2.2                          4

Answer 2

$2 {x}^{2} - 8x + 8 = 0 \\ \\ a = 2 \\ b = ( - 8) \\ c = 8 \\ \\ \Delta = {b}^{2} - 4ac \\ \Delta = {( - 8)}^{2} - 4 \times 2 \times 8 \\\Delta = 64 - 64 \\ \Delta = 0 \\ \\ x = \frac{ - b \pm \sqrt{\Delta} }{2a} \\ \\ x = \frac{ - ( - 8)\pm \sqrt{0} }{2 \times2} \\ \\ x = \frac{8\pm\diagup\!\!\!\!0}{4} \\ \\ x_{1 \: e \: 2} = \frac{8}{4} = 2$

S = {2}