Question

2x/6+3x/4+3=x/2-1/3
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Answer 1

$\frac{2x}{6}+\frac{3x}{4}+3=\frac{x}{2}-\frac{1}{3}$

$\frac{2x}{6}+\frac{3x}{4}-\frac{x}{2} =-\frac{1}{3}-3$

$\frac{4x}{12}+\frac{9x}{12}-\frac{6x}{12}=-\frac{1}{3}-\frac{9}{3}$

$\frac{7x}{12}=-\frac{10}{3}$

$\frac{7x}{4}=-10$

$7x=-10.4$

$7x=-40$

$x=-\frac{40}{7}$