Question

(2x + 6) *(-3x + 12) > 0.​

Answer 1

Resposta:

$\left(2x+6\right)\left(-3x+12\right)>0\\\\-x^2+x+12>0\\\\-\left(x+3\right)\left(x-4\right)>0\\\\\left(-\left(x+3\right)\left(x-4\right)\right)\left(-1\right)<0\cdot \left(-1\right)\\\\\left(x+3\right)\left(x-4\right)<0\\\\-3<x<4$

Answer 2

(2x + 6) *(-3x + 12) > 0

raízes

2x+6=0 ==>x=-3

-3x+12=0  ==>x=4

-6x²+36x-18x+72 > 0

-6x²+18x+72 > 0

a=-6<0 , concavidade p/baixo

----------------------------(-3)++++++++++++++++(4)-------------------------

(3 ; 4)   ou    -3 <  x < 4